kx^2 - 70x + 2k = 0

Find the maximum integral value of k for which the above quadratic equation has two distinct real roots.

Guest Jul 2, 2021

#1**+1 **

"*kx^2 - 70x + 2k = 0*

*Find the maximum integral value of k for which the above quadratic equation has two distinct real roots.*"

First find the value of k that gives exactly one root, then take the nearest integer saller than that.

To find the value of k that gives exactly one root, set the discriminant to zero. In this case that is:

70^2 - 4*k*2*k = 0

I'll leave you to solve for k etc.

Alan Jul 2, 2021